4(b-6)=b^2

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Solution for 4(b-6)=b^2 equation: 



4(b-6)=b^2

We move all terms to the left:

4(b-6)-(b^2)=0

determiningTheFunctionDomain
-b^2+4(b-6)=0

We add all the numbers together, and all the variables

-1b^2+4(b-6)=0

We multiply parentheses

-1b^2+4b-24=0

a = -1; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·(-1)·(-24)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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